How to find out whether a given number is even or odd?
Traditional way:
int number = 10;
if(number%2 == 0){
System.out.println("Even number");
}else{
System.out.println("Odd number");
}
Output:
Even number
But what we an interviewer asks, not to use operator (%). Then we will be in trouble :).
Enhanced way:
public class EvenOrOddNumber {
public static void main(String[] args) {
System.out.println(isEvenNumber(10));
System.out.println(isEvenNumber(13));
}
public static boolean isEvenNumber(int number){
return (number & 1) == 0 ? true : false;
}
}
Output:
true
false
Traditional way:
int number = 10;
if(number%2 == 0){
System.out.println("Even number");
}else{
System.out.println("Odd number");
}
Output:
Even number
But what we an interviewer asks, not to use operator (%). Then we will be in trouble :).
Enhanced way:
public class EvenOrOddNumber {
public static void main(String[] args) {
System.out.println(isEvenNumber(10));
System.out.println(isEvenNumber(13));
}
public static boolean isEvenNumber(int number){
return (number & 1) == 0 ? true : false;
}
}
Output:
true
false